This is unfortunately ,as i expected, a bitch to explain.
Quote:
"So if an engine at a constant load burns fuel at 14:1 at say 9000 rpm, a speed at which it pumps X cubic meter of air per minute . Then if the RPM increases to say 11,000 then the engine pumps 11/9 x X cubic meters of air so the fuel must increase by 11/9 or the mixture will go lean."
Yes the
total amount of fuel per minute will go up , but in
1 combustion cycle it will still burn the same amount of fuel: 1:14 of the cylinder capacity
whether the engine runs 1000,8000 or 10000 rpm it doesnt need to inject no more then 1/14 fuel to make 1 combustion,the number of combustions per minute will change but not the amount of fuel injected in 1 combustion.
You have to look at it PER COMBUSTION CYCLE.
If in 1 combustion cycle X gram of fuel is injected and this results in Y torque at 8000 rpm and if i can make the engine rev 2000 rpm higher while still injecting and burning the X amount of fuel PER CYCLE then HP has risen by 8000+2000:8000=10/8=1.25
The output of an injector is a: not fixed and b; depending on the number of times per minute the injector opens and closes.
So an injector can inject the same amount of fuel per opening/close cycle and result in a range of HP delivered by the engine ranging from 0 to 20 HP depending on the rpm the engine makes
HP= a value calculated over the amount of combustion cycles PER TIME, it does reflect the amount of fuel burnt in a certain time
Torque represents the amount of fuel burnt in 1 combustion cycle and not the amount of fuel burnt in 1 minute.
The calculation says hp=rpm x torque
The calculation says 6= 3 x 2
If torque (2) stays the same and rpm (3) goes up to 4 you get:
HP=4 x 2
HP=8
I have just risen the rpm by 1 while maintaining torque at the same level and so HP is risen.
Just a simple example with numbers that dont reflect reality but just to give you the idea:
Engine A:
rpm=8000
Injected fuel per combustion cycle= 1 gram/cycle and delivers with this 1 gram of fuel 10 nM torque.
HP= rpm X torque
HP= 8000 X 10
HP= 8000 HP
Engine B:
rpm=8000
Injected fuel per combustion cycle= 1 gram/cycle and delivers with this 1 gram of fuel 10 nM torque
HP= rpm X torque
HP= 10000 X 10
HP= 10000 HP
The numbers dont make sense (10000 hp
) but its the idea that counts.
So the amount of fuel PER CYCLE stays the same but because the engine is making more rpm you also inject MORE CYCLES PER MINUTE so you get more HP.
The amount of fuel injected each time it sprays stays the same but you inject more times PER MINUTE.
1 drop per minute ; few HP
Lots of drops per minute ; a lot of HP
But the DROP SIZE stays the same.
You may also conclude there are 2 ways of raising HP:
HP=torque x rpm
So you may raise the rpm and if
torque stays the same hp will go up
Or:
You may raise the torque and if
rpm stays the same hp will go up.
Failure is not an option, it comes bundled with the package.
